WebApr 12, 2024 · Ideally, I could simply tell the people who use this code "fill in the variables on the list command, and then run this command to destring everything within the list. Why would you use a list instead of a character vector for column names? If you use stringvars <- c ("var1", "var2") it will work just fine. I'm a big fan of lists, but don't use ... WebWatch how to convert a string variable to a numeric variable. Copyright 2011-2024 StataCorp LLC. All rights reserved.
How can I quickly convert many string variables to numeric …
WebNov 16, 2024 · destring itself has an STB history going back to 1997, and it may be that some users got used to the fact that it could encode en masse (and that, to these users, … WebMay 6, 2024 · destring year-unemp_rate, replace generate str county_fips = state_fips + county_fips_3 save county_20`y’.dta, replace clear} ... employed, and unemployed table year, c(sum labor_force sum employed sum unemployed) f(%20.0fc) This entry was posted in Research on May 6, 2024 by nwhillman. Post navigation photobump
Stata处理日期变量 - 知乎 - 知乎专栏
WebJun 24, 2024 · will convert the numeric characters to a numeric value. If the number of digits to be converted is greater than 7, then you will need to use one of the following: generate long wanted = real (substr (the_string_variable,3,.)) generate double wanted = real (substr (the_string_variable,3,.)) WebAug 30, 2024 · I am assuming that any two digit years (like "04") should be in this century ("2004"). Code: *create a new var date that is the label of interview date decode interviewdate, gen (date) *split date into parts split date, parse ("/") gen (d_) destring *fix the 2 digit years; change to 4 digit years replace d_3=real (string (2)+string (d_3, "%03 ... WebApr 17, 2015 · If your goal is, given a string variable year, to produce a daily date variable for 31 December in each year, then destring is not necessary. Here are three ways to do … photobygibson.com